What is the derivative of $-2/(2x-4)^2$ ?

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Answer 1 · 2017-03-01T17:45:48

$d/dx -2/(2x-4)^2 =1/(x-2)^3$

$d/dx -2/(2x-4)^2 = d/dx -2/((2(x-2))^2)$
$" "= d/dx -2/(4(x-2)^2)$
$" "= d/dx -1/2 (x-2)^(-2)$

So applying the power rule we get;

$d/dx -2/(2x-4)^2 = -1/2 (-2)(x-2)^(-3)$
$" "= 1(x-2)^(-3)$
$" "= 1/(x-2)^3$

What is the derivative of -2/(2x-4)^2-2/(2x-4)^2?