What is the derivative of 5/x^7? Calculus Basic Differentiation Rules Quotient Rule 1 Answer ali ergin May 25, 2016 (d y)/(d x)=-35x^-8 Explanation: y=5/x^7 y=a/b" "y^'=(a^'*b-b^'*a)/b^2 (d y)/(d x)=(0*x^7-7*x^6*5)/x^(14) (d y)/(d x)=-(35x^6)/x^14 (d y)/(d x)=-(35)/x^8" "=-35*x^-8 " or :" y=5*x^-7 y=a*b y^'=a^'*b+b^'*a (d y)/(d x)=-7*0*x^-8-7*x^-8*5 (d y)/(d x)=0-35x^-8 (d y)/(d x)=-35x^-8 Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate y=(2x^4-3x)/(4x-1)? How do you use the quotient rule to differentiate y=cos(x)/ln(x)? How do you use the quotient rule to find the derivative of y=tan(x) ? How do you use the quotient rule to find the derivative of y=x/(x^2+1) ? How do you use the quotient rule to find the derivative of y=(e^x+1)/(e^x-1) ? How do you use the quotient rule to find the derivative of y=(x-sqrt(x))/(x^(1/3)) ? How do you use the quotient rule to find the derivative of y=x/(3+e^x) ? See all questions in Quotient Rule Impact of this question 3587 views around the world You can reuse this answer Creative Commons License