What is the derivative of 5/x^7?

1 Answer
May 25, 2016

(d y)/(d x)=-35x^-8

Explanation:

y=5/x^7

y=a/b" "y^'=(a^'*b-b^'*a)/b^2

(d y)/(d x)=(0*x^7-7*x^6*5)/x^(14)

(d y)/(d x)=-(35x^6)/x^14

(d y)/(d x)=-(35)/x^8" "=-35*x^-8

" or :"

y=5*x^-7

y=a*b

y^'=a^'*b+b^'*a

(d y)/(d x)=-7*0*x^-8-7*x^-8*5

(d y)/(d x)=0-35x^-8

(d y)/(d x)=-35x^-8