What is the derivative of (6)/(x^3sqrtx)? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Massimiliano Apr 30, 2015 The answer is: y'=-21/(x^4sqrtx). The function can be written: y=6*x^(-3-1/2)rArry=6x^(-7/2) y'=6*(-7/2)*x^(-7/2-1)=-21x^(-9/2)=-21/sqrt(x^9)= =-21/(x^4sqrtx). Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate y=(2x^4-3x)/(4x-1)? How do you use the quotient rule to differentiate y=cos(x)/ln(x)? How do you use the quotient rule to find the derivative of y=tan(x) ? How do you use the quotient rule to find the derivative of y=x/(x^2+1) ? How do you use the quotient rule to find the derivative of y=(e^x+1)/(e^x-1) ? How do you use the quotient rule to find the derivative of y=(x-sqrt(x))/(x^(1/3)) ? How do you use the quotient rule to find the derivative of y=x/(3+e^x) ? See all questions in Quotient Rule Impact of this question 1503 views around the world You can reuse this answer Creative Commons License