What is the derivative of $y= (x^2 + 2x + 5) / (x + 1)$ ?

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Answer 1 · 2015-04-17T18:27:29

$y = (x^2 + 2x + 5)/(x + 1)$

$=> (dy)/(dx) = ((x + 1)(2x + 2) - (x ^2 + 2x + 5)(1))/(x + 1)^2$

$= (2x^2 + 4x + 2 - x^2 - 2x - 5)/(x + 1)^2 = (x^2 + 2x - 3)/(x + 1)^2$

What is the derivative of y= (x^2 + 2x + 5) / (x + 1)y= (x^2 + 2x + 5) / (x + 1)?