What is the Integral of $1/tan(x) dx$ ?

May 6, 2016

$lnabs(sinx) +C$

$1/tanx = cotx = cosx/sinx$

$int1/tanx dx= intcotx dx$

$= int cosx/sinx dx$

Let $u = sinx$ , so $du = cosx dx$ to get

$= int 1/u du$

$= ln absu +C$

$= ln abs sinx +C$

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What is the Integral of 1/tan(x) dx1/tan(x) dx?