What is the integral of int cos(x)sin(sin(x))dxcos(x)sin(sin(x))dx?

1 Answer
Feb 6, 2016

-cos(sin(x))+Ccos(sin(x))+C.

Explanation:

To begin, start by considering the substitution: u = sin(x)u=sin(x)

So we also have that: du = cos(x)dxdu=cos(x)dx

Substituting that into the integral will give:

intcos(x)sin(sin(x))dx = intsin(u)ducos(x)sin(sin(x))dx=sin(u)du

We can now integrate to obtain:

=-cos(u) + C=cos(u)+C

And reversing the substitution we are left with:

=-cos(sin(x))+C=cos(sin(x))+C.