What is the integral of $int tan^2(3x)dx$ ?

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Answer 1 · 2016-01-17T02:44:30

$int tan^2(3x) dx = 1/3 tan(3x) - x + C$

where $C$ is the constant of integration

You should know the identity $tan^2theta-=sec^2theta-1$ .

$int tan^2(3x) dx = int (sec^2(3x)-1) dx$

$= 1/3 tan(3x) - x + C$

where $C$ is the constant of integration.

What is the integral of int tan^2(3x)dxint tan^2(3x)dx?