What is the integral of tan^2(x)? Calculus Introduction to Integration Integrals of Trigonometric Functions 1 Answer Mika Dec 19, 2014 Use the identity tan^2x=sec^2x-1 int tan^2x dx =int sec^2x - 1 dx =int sec^2x dx - int dx Integrate separately and you'll get. tanx - x Answer link Related questions How do I evaluate the indefinite integral intsin^3(x)*cos^2(x)dx ? How do I evaluate the indefinite integral intsin^6(x)*cos^3(x)dx ? How do I evaluate the indefinite integral intcos^5(x)dx ? How do I evaluate the indefinite integral intsin^2(2t)dt ? How do I evaluate the indefinite integral int(1+cos(x))^2dx ? How do I evaluate the indefinite integral intsec^2(x)*tan(x)dx ? How do I evaluate the indefinite integral intcot^5(x)*sin^4(x)dx ? How do I evaluate the indefinite integral inttan^2(x)dx ? How do I evaluate the indefinite integral int(tan^2(x)+tan^4(x))^2dx ? How do I evaluate the indefinite integral intx*sin(x)*tan(x)dx ? See all questions in Integrals of Trigonometric Functions Impact of this question 2043 views around the world You can reuse this answer Creative Commons License