What's the integral of int 1/(secx+tanx)dx?

1 Answer
ali ergin
Mar 6, 2016

int 1/(sec x+tan x)d x=l n(1+sin x) + C

Explanation:

int 1/(sec x+tan x)d x=(d x)/(1/cos x+sin x/cos x)
int (cos x d x)/(1+sin x)" "1+sin x=u" "cos x d x=d u
int (d u)/u
int 1/(sec x+tan x)d x=l n u +C
int 1/(sec x+tan x)d x=l n(1+sin x) + C

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