How do you find the derivative of #3^x#?

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Answer 1 · 2016-11-23T15:39:08

#(dy)/(dx)=3^xln3#

using logarithmic differentiation

#y=3^x#

take natural logs to both sides

#lny=ln3^x=xln3#

differentiate #wrt" " x#

#1/y(dy)/(dx)=ln3#

#(dy)/(dx)=yln3#

substitute back

#(dy)/(dx)=3^xln3#