Question

How do you differentiate `y=3e^x-7log_10x`?

Answer 1

`y'=3e^x-7/x`

Explanation:

Differentiating the `e` part:

rule: leave the `e^x` then multiply by the differential of the power.

So it's `3e^x*1=3e^x`

Log part:

rule: function on the bottom, differential on the top

So `-7*log_10x` becomes `-7*1/x = -7/x`