Question #9e2ee Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Gió Feb 26, 2015 You get: y'=1*e^(2x)+x*2e^(2x)=e^(2x)+2xe^(2x)=e^(2x)(2x+1) y''=2e^(2x)(2x+1)+e^(2x)*2=4xe^(2x)+2e^(2x)+2e^(2x)= =4xe^(2x)+4e^(2x) Answer link Related questions What is the derivative of y=3x^2e^(5x) ? What is the derivative of y=e^(3-2x) ? What is the derivative of f(theta)=e^(sin2theta) ? What is the derivative of f(x)=(e^(1/x))/x^2 ? What is the derivative of f(x)=e^(pix)*cos(6x) ? What is the derivative of f(x)=x^4*e^sqrt(x) ? What is the derivative of f(x)=e^(-6x)+e ? How do you find the derivative of y=e^x? How do you find the derivative of y=e^(1/x)? How do you find the derivative of y=e^(2x)? See all questions in Differentiating Exponential Functions with Base e Impact of this question 5289 views around the world You can reuse this answer Creative Commons License