Question #c2366

1 Answer
sjc
Nov 2, 2016

(dy)/(dx)=2atan(ax+b)sec^2(ax+b)

Explanation:

y=tan^2(ax+b)

u=ax+b=>(du)/(dx)=a

y=tan^2u=>(dy)/(du)=2tanusec^2u

(dy)/(dx)=(dy)/(du)xx(du)/(dx)

(dy)/(dx)=(2tanusec^2u)xxa

(dy)/(dx)=2atan(ax+b)sec^2(ax+b)

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