Given $f(x)= e^x ln(x)$ how do you find find f'(1)?

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Answer 1 · 2016-06-17T05:24:25

$f'(x)=e$

As $f(x)=e^xlnx$

$f'(x)=e^x xx1/x+e^xlnx$

Hence $f'(x)=e^1 xx1/1+e^1xxln1$

= $exx1+exx0=e$

Given f(x)= e^x ln(x)f(x)= e^x ln(x) how do you find find f'(1)?