How do you differentiate $9^{x}$ $9^x$ ?

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Answer 1 · 2016-08-26T12:44:43

$ln 9 \cdot 9^{x}$ $ln9*9^x$

$f (x) = 9^{x}$ $f(x) = 9^x$

$ln f (x) = x ln 9$ $lnf(x) = xln9$

$1/f(x)*f'(x) = ln9$ (Implicit differentiation)

$f'(x) = ln9*f(x)$

$= ln9*9^x$

How do you differentiate 9^x9x9^x?