How do you differentiate $f(x)= (e^x-e^-x) / 2$ ?

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Answer 1 · 2016-08-01T09:30:03

$= (e^x+e^-x) / 2$

$d/dx ((e^x-e^-x) / 2)$

$= d/dx (e^x/2) - d/dx( (e^-x) / 2)$

$= e^x/2 - (-e^-x) / 2$

$= (e^x+e^-x) / 2$

or if you like.....

$d/dx ((e^x-e^-x) / 2)$

$= d/dx sinh x$

$= cosh x$

$= (e^x+e^-x) / 2$

How do you differentiate f(x)= (e^x-e^-x) / 2 f(x)= (e^x-e^-x) / 2?