How do you differentiate $f (x) = ln (\frac{1}{e})$ $f(x) = ln (1/e)$ ?

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Answer 1 · 2015-03-27T01:46:10

$ln (\frac{1}{e}) = ln (e^{- 1} = - 1$ $ln(1/e)=ln(e^(-1)=-1$ So $f (x) = ln (\frac{1}{e}) = - 1$ $f(x)=ln(1/e)=-1$

$f'(x)=0$

How do you differentiate f(x) = ln (1/e)f(x)=ln(1e)f(x) = ln (1/e)?