How do you differentiate $f(x) = x^2 - 4x + 3$ ?

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Answer 1 · 2015-04-01T23:51:54

Remember that if you differentiate $x^n$ you get $nx^(n-1)$ .
So, in your case:
$(df)/dx=2x-4$

(the constant $3$ gives you zero)

How do you differentiate f(x) = x^2 - 4x + 3f(x) = x^2 - 4x + 3?