How do you differentiate $y = 10^(1-x^2)$ ?

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Answer 1 · 2016-06-24T18:08:53

$y' = -2x * ln(10) * 10^(1-x^2)$

$y = 10^(1-x^2)$
$ln y = (1-x^2)ln(10)$
$1/y \ y' = -2x * ln(10)$
$y' = -2x * ln(10) * 10^(1-x^2)$

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How do you differentiate y = 10^(1-x^2)y = 10^(1-x^2)?