How do you differentiate $y= 10^ (tan (pi)(theta)$ ?

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Answer 1 · 2017-01-18T18:05:49

$dy/(dθ) = 10^tan(πθ) (πln(tan(πθ))) /cos^2(πθ)$

Let $v = πθ$ and $u = tanv$ .
Using the chain rule, $dy/(dθ) = dy/(du) (du)/(dv) (dv)/(dθ)$

So now, $y = 10^u$ , so:

$dy/(dθ) = 10^u lnu * 1/cos^2(v) * π$

$= 10^tan(πθ) (πln(tan(πθ))) /cos^2(πθ)$

How do you differentiate y= 10^ (tan (pi)(theta)y= 10^ (tan (pi)(theta)?