How do you differentiate $y=(3/2)^x$ ?

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Answer 1 · 2016-09-15T17:34:07

$((3) / (2))^(x) cdot ln((3) / (2))$

We have: $y = ((3) / (2))^(x)$

The derivative of any function of the form $f(x) = a^(x)$ is given as: $f'(x) = a^(x) ln(a)$

$=> (d) / (dx) (((3) / (2))^(x)) = ((3) / (2))^(x) cdot ln((3) / (2))$

How do you differentiate y=(3/2)^xy=(3/2)^x?