How do you differentiate $y=3e^x-7log_10x$ ?

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Answer 1 · 2017-11-29T21:11:08

$y'=3e^x-7/x$

Differentiating the $e$ part:

rule: leave the $e^x$ then multiply by the differential of the power.

So it's $3e^x*1=3e^x$

Log part:

rule: function on the bottom, differential on the top

So $-7*log_10x$ becomes $-7*1/x = -7/x$

How do you differentiate y=3e^x-7log_10xy=3e^x-7log_10x?