How do you differentiate $y=7^(x^2)$ ?

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Answer 1 · 2017-02-05T22:17:18

$y=7^(x^2) => y'=(2ln(7)x)7^(x^2)$

Since $forall r in RR, x^r=e^(rln(x))$

It is true that

$7^(x^2)=e^(x^2ln(7))$

Then by the chain rule $(f(g(x)))'=f'(g(x))g'(x)$

$=> (e^(x^2ln(7)))'=e^(x^2ln(7))2ln(7)x=7^(x^2)(2ln(7)x)$

How do you differentiate y=7^(x^2)y=7^(x^2)?