How do you differentiate $y=(e^x(x^2-7))$ ?

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Answer 1 · 2016-10-05T15:11:39

$f'(x)=e^x(x^2+2x-7)$

You have to use the Product Rule

$f'(x)=uv'+u'v$

$u=e^x$
$u'=e^x$

$v=x^2-7$
$v'=2x$

$f'(x)=e^x2x+e^x(x^2-7)$

Factor out $e^x$

$f'(x)=e^x(x^2+2x-7)$

How do you differentiate y=(e^x(x^2-7))y=(e^x(x^2-7))?