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How do you differentiate $y = ln (e^{- x} + x e^{- x})$ $y=ln(e^-x + xe^-x)$ ?

1 Answer

Apr 23, 2016

$y' = -x/(1+x)$

Explanation:

Write y = ln f
then y' = f'/f
$f' = - x e^-x$
$y' = -x/(1+x)$

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