How do you find the 1st and 2nd derivative of $2e^(2x)$ ?

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Answer 1 · 2016-10-07T14:25:22

Using $d/dx e^(mx)=me^x$

so $d/dx 2e^(2x)=2d/dx e^(2x)=2(2e^(2x))=4e^(2x)$
And so, The $d^2/dx^2 2e^(2x)=d/dx 4e^(2x)=4(2e^(2x))=8e^(2x)$

How do you find the 1st and 2nd derivative of 2e^(2x)2e^(2x)?