How do you find the derivative of $(2x)/(3+e^x)$ ?

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Answer 1 · 2018-03-07T04:35:10

$(6+2e^x - 2xe^x)/(3+e^x)^2$

$d/dx(f/g) = (gf' - fg')/g^2$

If $f(x) = 2x$ and $g(x) = 3 + e^x$ , the derivative is

$(2(3+e^x) - 2x(e^x))/(3+e^x)^2 = (6+2e^x - 2xe^x)/(3+e^x)^2$

How do you find the derivative of (2x)/(3+e^x)(2x)/(3+e^x)?