How do you find the derivative of $(e^(2x))/(4^x)$ ?

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Answer 1 · 2018-06-16T10:36:57

$(e^(2x)(1-ln(2)))/(2^(2x-1))$

$(u/v)'=(u'v-uv')/v^2$

we get

$f'(x)=(e^(2x)2*4^x-e^(2x)*4^x*ln(4))/(4^x)^2$
simplifying we get

$(e^(2x)(1-ln(2)))/(2^(4x-2x-1))$
and this is equal to

$(e^(2x)(1-ln(2)))/(2^(2x-1))$

How do you find the derivative of (e^(2x))/(4^x)(e^(2x))/(4^x)?