How do you find the derivative of $ln((x^2)(e^x))$ ?

Question

1541 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-10T20:34:30

Apply the additive property of logs hence we have that

$ln(x^2*e^x)=ln(x^2)+ln(e^x)=2*lnx+x$

Hence the derivative is

$d(2*lnx+x)/dx=2/x+1$

for values of $x>0$

How do you find the derivative of ln((x^2)(e^x))ln((x^2)(e^x))?