How do you find the derivative of $s=3^(t+1)$ ?

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Answer 1 · 2017-05-18T12:59:09

$(ds)/(dt)=(3^(t+1))ln3$

for these type of problems we use logarithmic differentiation

$s=3^(t+1)$

$=>lns=Ln(3^(t+1))$

$=>lns=(t+1)ln3$

differentiate wrt $t$

$1/s (ds)/(dt)=ln3$

$(ds)/(dt)=sln3$

substituting back for $s$

$(ds)/(dt)=(3^(t+1))ln3$

How do you find the derivative of s=3^(t+1)s=3^(t+1)?