How do you find the derivative of $y=3^sqrtx$ ?

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Answer 1 · 2017-06-22T06:58:10

$(dy)/(dx)=(3^(sqrtx)ln3)/(2sqrtx)$

A $y=3^(sqrtx)$

$lny=sqrtxln3$

and $1/y(dy)/(dx)=1/(2sqrtx)xxln3$

or $(dy)/(dx)=ln3/(2sqrtx)xxy=ln3/(2sqrtx)xx3^(sqrtx)=(3^(sqrtx)ln3)/(2sqrtx)$

How do you find the derivative of y=3^sqrtxy=3^sqrtx?