How do you find the derivative of $y=e^(3x+4)$ ?

Question

14342 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-09T13:36:33

$3e^(3x+4)$

Given: $y=e^(3x+4)$

Use the chain rule, which states that,

$dy/dx=dy/(du)*(du)/dx$

Let $u=3x+4,:.du=3 \ dx,(du)/dx=3$ .

Here, $y=e^u,:.dy=e^u \ du,dy/(du)=e^u$ .

Multiplying those results together, we get,

$dy/dx=e^u*3$

$=3e^u$

Substituting back $u=3x+4$ , we get,

$=3e^(3x+4)$

How do you find the derivative of y=e^(3x+4)y=e^(3x+4)?