What is the derivative of $2^(cosx)$ ?

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Answer 1 · 2017-01-10T19:45:25

$(dy)/(dx)=-log2sinx2^(cosx)$

Making $y=2^(cosx)$ and applying $log$ to both sides

$log y = cosx log2$ Deriving now

$(dy)/y=-log2sinx dx$ Rearranging

$(dy)/(dx)=-log2ysinx=-log2sinx2^(cosx)$

What is the derivative of 2^(cosx)2^(cosx)?