What is the derivative of $2^x$ ?

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Answer 1 · 2018-03-17T16:25:58

Derivative of $2^x$ is $2^xln2$

Let $y=2^x$ . Now to find $(dy)/(dx)$ , let us take logarithm on both sides, which gives

$lny=xln2$ - now taking implicit differential on both sides

$1/y(dy)/(dx)=ln2$

and hence $(dy)/(dx)=yln2=2^xln2$

What is the derivative of 2^x2^x?