What is the derivative of 5^tanx?

1 Answer
Jul 17, 2015

Let's derive what the derivative is, because I don't remember what it is (yet).

log_5(y) = log_5(5^tanx) = tanx

Change of Base law:
(lny)/(ln5) = tanx

lny = tanx ln5

Implicit Differentiation:
1/y((dy)/(dx)) = ln5 * sec^2x

(dy)/(dx) = y[ln5 * sec^2x]

= color(blue)(5^(tanx)[ln5*sec^2x])

Yep, there it is. So then the general derivative is:

color(green)(d/(dx)[b^u] = b^u*lnb*(du)/(dx))

(see how you can just figure it out without remembering it? It's a trick.)