How do you express #cos(pi/ 3 ) * cos (( pi) / 6 ) # without using products of trigonometric functions?
1 Answer
The final answer is
Explanation:
For Trig functions, here is your best friend, the trig circle.
What you see here is for every section of the circle you have, there is a value for the cosine and sine for that value.
Therefore if you look at the line of
When you look at the line
Then the multiplication of
#1/2*sqrt3/2=sqrt3/4#