Strategies to Test an Infinite Series for Convergence

Key Questions

  • By pulling out the negative sign so that a_n ge0, let

    -sum_{n=1}^inftya_n=-sum_{n=1}^infty{n^2+2^n}/{e^{n+1}-1}.

    I would use Limit Comparison Test since we can make a ball-park estimate of the series by only looking at the dominant terms on the numerator and the denominator. This series can be compared to

    sum_{n=1}^inftyb_n=sum_{n=1}^infty{2^n}/{e^{n+1}}=sum_{n=1}^infty1/e(2/e)^n,

    which is a convergent geometric series with |r|=|2/e|<1.

    Let us make sure that they are comparable.

    lim_{n to infty}{a_n}/{b_n}=lim_{n to infty}{{n^2+2^n}/{e^{n+1}-1}}/{{2^n}/{e^{n+1}}}

    =lim_{n to infty}{{n^2}/{2^n}+1}/{1-1/e^{n+1}}={0+1}/{1-0}=1 < infty

    (Note: lim_{n to infty}{n^2}/2^n=0 by applying l'Hopital's Rule twice.)

    So, sum_{n=1}^infty a_n converges by Limit Comparison Test.

    Hence, sum_{n=1}^infty{n^2+2^n}/{1-e^{n+1}} also converges since negation does not affect the convergence of the series.


    I hope that this was helpful.

  • There is no general method of determining the test you should use to check the convergence of a series.

    • For series where the general term has exponents of n, it's useful to use the root test (also known as Cauchy's test).
      Example 1: Power Series
      The definition of the convergence radius of the of a power series comes from the Cauchy test (however, the actual computation is usually done with the following test).

    • Generally, the computation of the ratio test (also known as d'Alebert's test) is easier than the computation of the root test.
      Example 2: Inverse Factorial
      For the series sum_(n=1)^(oo) 1/(n!) the d'Alembert's test gives us:
      lim_(n to oo) |1/((n+1)!)|/|1/(n!)| = lim_(n to oo) |n!|/(|(n+1)!|) = lim_(n to oo) |(n!)/((n+1)n!)| = lim_(n to oo) |1/(n+1)| = 0
      So the series is convergent.

    • If you know the result of the improper integral of the function f(x) such that f(n)=a_n, where a_n is the general term of the series being analyzed, then it might be a good idea to use the integral test.
      Example 3: A proof for the Harmonic Series.
      Knowing that the improper integral int_1^(oo) 1/x dx is divergent (it's easy to check) implies that the harmonic series sum_(n=1)^(oo) 1/(n) diverges.

    • Comparision tests are only useful if you know an appropriate series to compare the one you're analyzing to. However, they can be very powerful.
      Example 4: Hyperharmonic Series
      The series of the form sum_(n=1)^(oo) 1/(n^p) are called hyperharmonic series or p-series. If you can show that the series sum_(n=1)^(oo) 1/(n^(1+epsilon)) converges, for some small, positive value of epsilon, than any p-series such that p>1 + epsilon converges.

Questions