Alternating Series Test (Leibniz's Theorem) for Convergence of an Infinite Series

Key Questions

  • In most cases, an alternation series sum_{n=0}^infty(-1)^nb_n fails Alternating Series Test by violating lim_{n to infty}b_n=0. If that is the case, you may conclude that the series diverges by Divergence (Nth Term) Test.

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  • Alternating Series Test

    An alternating series sum_{n=1}^infty(-1)^n b_n, b_n ge 0 converges if both of the following conditions hold.

    {(b_n ge b_{n+1} " for all " n ge N),(lim_{n to infty}b_n=0):}


    Let us look at the posted alternating series.

    In this series, b_n=1/sqrt{3n+1}.

    b_n=1/sqrt{3n+1} ge 1/sqrt{3(n+1)+1}=b_{n+1} for all n ge 1.

    and

    lim_{n to infty}b_n=lim_{n to infty}1/sqrt{3n+1}=1/infty=0

    Hence, we conclude that the series converges by Alternating Series Test.


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  • Alternating Series Test states that an alternating series of the form
    sum_{n=1}^infty (-1)^nb_n, where b_n ge0,
    converges if the following two conditions are satisfied:
    1. b_n ge b_{n+1} for all n ge N, where N is some natural number.
    2. lim_{n to infty}b_n=0

    Let us look at the alternating harmonic series sum_{n=1}^infty (-1)^{n-1}1/n.
    In this series, b_n=1/n. Let us check the two conditions.
    1. 1/n ge 1/{n+1} for all n ge 1
    2. lim_{n to infty}1/n=0

    Hence, we conclude that the alternating harmonic series converges.

Questions