Alternating Series Test (Leibniz's Theorem) for Convergence of an Infinite Series
Key Questions
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In most cases, an alternation series
sum_{n=0}^infty(-1)^nb_n fails Alternating Series Test by violatinglim_{n to infty}b_n=0 . If that is the case, you may conclude that the series diverges by Divergence (Nth Term) Test.I hope that this was helpful.
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Alternating Series Test
An alternating series
sum_{n=1}^infty(-1)^n b_n ,b_n ge 0 converges if both of the following conditions hold.{(b_n ge b_{n+1} " for all " n ge N),(lim_{n to infty}b_n=0):}
Let us look at the posted alternating series.
In this series,
b_n=1/sqrt{3n+1} .b_n=1/sqrt{3n+1} ge 1/sqrt{3(n+1)+1}=b_{n+1} for alln ge 1 .and
lim_{n to infty}b_n=lim_{n to infty}1/sqrt{3n+1}=1/infty=0 Hence, we conclude that the series converges by Alternating Series Test.
I hope that this was helpful.
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Alternating Series Test states that an alternating series of the form
sum_{n=1}^infty (-1)^nb_n , whereb_n ge0 ,
converges if the following two conditions are satisfied:
1.b_n ge b_{n+1} for alln ge N , whereN is some natural number.
2.lim_{n to infty}b_n=0 Let us look at the alternating harmonic series
sum_{n=1}^infty (-1)^{n-1}1/n .
In this series,b_n=1/n . Let us check the two conditions.
1.1/n ge 1/{n+1} for alln ge 1
2.lim_{n to infty}1/n=0 Hence, we conclude that the alternating harmonic series converges.
Questions
Tests of Convergence / Divergence
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Geometric Series
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Nth Term Test for Divergence of an Infinite Series
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Direct Comparison Test for Convergence of an Infinite Series
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Ratio Test for Convergence of an Infinite Series
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Integral Test for Convergence of an Infinite Series
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Limit Comparison Test for Convergence of an Infinite Series
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Alternating Series Test (Leibniz's Theorem) for Convergence of an Infinite Series
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Infinite Sequences
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Root Test for for Convergence of an Infinite Series
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Infinite Series
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Strategies to Test an Infinite Series for Convergence
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Harmonic Series
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Indeterminate Forms and de L'hospital's Rule
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Partial Sums of Infinite Series