Question #da364

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Question #da364

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Answer 1 · 2016-08-03T23:31:56

$x = - 30$ $x=-30$
$x = 20$ $x=20$

Explanation:

$tan 2 x = - \sqrt{3}$ $tan2x=-sqrt3$
or
$2 x = {tan}^{- 1} (- \sqrt{3})$ $2x=tan^-1(-sqrt3)$
or
$2 x = - 60$ $2x=-60$
or
$x = - \frac{60}{2}$ $x=-60/2$
or
$x = - 30$ $x=-30$ ===========Ans $1$ $1$
$2 sin 3 x - \sqrt{3} = 0$ $2sin3x-sqrt3=0$
or
$2 sin 3 x = \sqrt{3}$ $2sin3x=sqrt3$
or
$sin 3 x = \frac{\sqrt{3}}{2}$ $sin3x=sqrt3/2$
or
$3 x = {sin}^{- 1} (\frac{\sqrt{3}}{2})$ $3x=sin^-1(sqrt3/2)$
or
$3 x = 60$ $3x=60$
or
$x = \frac{60}{3}$ $x=60/3$
or
$x = 20$ $x=20$ ==========Ans $2$ $2$

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Question #da364

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