Convert 5cos((5pi)/3)cos((5pi)/3)5cos(5π3)cos(5π3) as a sum of trigonometric ratios?
1 Answer
Mar 29, 2017
=
Explanation:
As
adding the two we get
Hence
=5/2xx2cos((5pi)/3)cos((5pi)/3)=52×2cos(5π3)cos(5π3)
=5/2xx(cos((5pi)/3+(5pi)/3)+cos((5pi)/3-(5pi)/3))=52×(cos(5π3+5π3)+cos(5π3−5π3))
=5/2xx(cos((10pi)/3)+cos0)=52×(cos(10π3)+cos0) , butcos0=1cos0=1
Hence